Ranga Nathan wrote: > 02 s1n1 s1n2 3 s2n1 s2n2 s2n3 1 s3n1 4 s4n1 s4n2 s4n3 s4n4
if your count of items is alway s\d+ and your items always include non \d, couldn't you pick it off that way? my $cnt = '(\d+)'; my $item = '(s\dn\d)'; $str =~ /$cnt ($item )+/ this should slurp up as many items as possible. course, you're input could have an error with a count of 3 followed by 4 items, but you could check that after. if your items are indistinguishable from the count, then this won't work. Greg _______________________________________________ Boston-pm mailing list [EMAIL PROTECTED] http://mail.pm.org/mailman/listinfo/boston-pm
