Consider this snippet:
function f(x: any)
{
switch (x)
{
case type any:
print "any";
break;
case type vector of any:
print "vector of any";
break;
}
}
event bro_init()
{
f(42);
}
I would have imagined that the two cases are considered different types,
but Bro doesn't think so:
error in ./test.bro, lines 9-10: duplicate case label (case type vector of
any:{ print anybreak })
Adding a type alias for either type doesn't change the error message.
I am aware that this is a somewhat pathological case, because 'case type
any' is probably equivalent to the 'default' case.
Matthias
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