Re: [Bug-apl] defining new operator

[Juergen Sauermann]

Hi Fausto, page 30 (Defined Functions and Operators) explains it. In your example below F is expected to be a function because it is inside () in the header while the variable(s) are outside (). /// Jürgen On 04/14/2015 12:42 PM, Fausto Saporito wrote: Hello all, sorry if I bother you again, but I tried to find some hints in the APL2 Language Reference Manual without luck. In the Sullivan's paper, there's the reference to a "scan" operator quite fast more suited to be used with his multi precision package. This is its definition: ∇ z←(F scan)x;y z←⊂y←⊃x ∆1:!(0=⍴x←1"x)/0 z,←⊂y←y F⊃x  !∆1  the "!" is the branch arrow. Now the problem is with GNU APL I cannot define this operator, cause I don't know how to specify F is a function not a variable. is there a way to do that ?  thanks, fausto