With the demo version of APL2 I get:
5J3 ∣ 14J5
¯4J1
5J3 | 1J4
¯4J1
5J3 | ¯4J1
¯4J1
Jay.
On 19 June 2017 at 18:03, Frederick Pitts <[email protected]> wrote:
> Jürgen,
>
> With gnu apl (svn 961 on Fedora 25, Intel(R) Core(TM) i7-6700
> CPU), the residue function (∣) yields the following:
>
> 5J3 ∣ 14J5
> 1J4
> 5J3 | 1J4
> ¯4J1
> 5J3 | ¯4J1
> ¯4J1
> The above result means that two elements in the complete residue system
> (CSR) for mod 5J3 are equal, i.e. 1J4 = ¯4J1 mod 5J3, which is not
> allowed. None of the elements of a CSR can be equal modulo the CSR's
> basis.
>
> Regards,
>
> Fred
>
>
