Re: Incorrect results with unique of 20 or more elements

[Kacper Gutowski]

Actually, while the algorithm used for 20≥⍴ works well with 
characters or integers (once you fix the direction of 
inequality), I don't think it's actually correct at all for 
non-zero ⎕CT because tolerant equality is not transitive. 

Consider this: 

      X←1+0 1 2 5 4 3×(⎕CT←1E¯9)÷2
      ∪19↑X
1 1.000000001 1.000000002 0
      ∪20↑X
1.000000001 1.000000002 0
Both expressions should give the same result. 

-k