Re: ¨ (each) on defined function on array of empty arrays

[Ben Harris]

On Sun, 31 May 2020, Dr. Jürgen Sauermann wrote:

thanks, fixed in SVN 1290.

Thank you!  That seems to have left some more misbehaviour around "each", 
this time with scalars containing arrays passed to defined functions:

      (⊂0 0)≡¨((0 0) (0 1))
1 0
      ∇z ← x eq y
[1] z ← x ≡ y
[2] ∇
      (⊂0 0)eq¨((0 0) (0 1))
0 0

Here I'd expect eq and ≡ to behave identically, but they don't.  There 
are no empty arrays here, so no fill functions or identity functions are 
involved.

--
Ben Harris