> > (1) rlogin to a foreign host > > (2) Invoke a subshell (for example because I'm setting a > Clearcase > > View) > > Is it a subshell or a second-level shell? (In the first case, $$ and > $PPID remain the same.)
Could you kindly explain the difference? I thought it's always the same - a process (being the current shell, or cleartool, or whatever) is doing a fork, followed by an exec of the new shell. In the particular case of "cleartool setview", I don't know how it is done, but here is an example of the PIDs: $ echo $$ 25494 $ echo $PPID 25493 $ cleartool setview rofi_dft $ echo $$ 2965 $ echo $PPID 25494 So PPID changed (which I thought is very natural, since I have a new parent process now). The same effect appears if I invoke "zsh" instead of "cleartool....", so we have what you call a "second-level shell". Now I wonder what exactly would be a "subshell" then.... > Each subshell can use a trap to be able > to kill its parent. But bash and zsh behave differently concerning > traps. I can't use traps here, because I know only at "exit time", whether I want to logout completely, or just go up one level. > Alternatively, the command that invokes the subshell could call > 'exit' after it has finished (you can write a wrapper, e.g. as a > shell function). Here again, I would need to decide at the time I'm calling the subshell, what to do at the exit-time.... so not useful for me either. Regards, Ronald -- Ronald Fischer (phone +49-89-63676431) mailto:[EMAIL PROTECTED] _______________________________________________ Bug-bash mailing list Bug-bash@gnu.org http://lists.gnu.org/mailman/listinfo/bug-bash
