> It's worth noting here that bash's globbing of '[A-Z]*' etc is
> definitely different from the system collation sequence (i.e. using
> fnmatch() or glob() functions). There is an open bug report about this
> here:
On the contrary, the bash globbing of [A-Z] is using exactly the system's
collating sequence. Bash uses strcoll; glibc/python probably use character
value comparisons for old-style bracket range expressions.
Running the attached program like
asort -v {a..z} {A..Z}
will give you the current locale and show how the arguments sort. I get
$ ./asort -v {a..z} {A..Z}
default locale = en_US.UTF-8
a A b B c C d D e E f F g G h H i I j J k K l L m M n N o O p P q Q r R s S t T
u U v V w W x X y Y z Z
$ LC_ALL=en_US ./asort {a..z} {A..Z}
a A b B c C d D e E f F g G h H i I j J k K l L m M n N o O p P q Q r R s S t T
u U v V w W x X y Y z Z
This shows the collating sequence for alphabetics in the en_US locale. (Since
I don't set LC_ALL anywhere in my startup files, my system's default locale is
apparently en_US.UTF-8.)
Chet
#include <stdio.h>
#include <locale.h>
#include <string.h>
#include <stdlib.h>
#include <unistd.h>
static int
qsort_strcmp(s1, s2)
char **s1, **s2;
{
return (strcoll(*s1, *s2));
}
static void
usage()
{
fprintf(stderr, "asort: usage: asort [-v] args\n");
}
int
main(c, v)
int c;
char **v;
{
int i, verbose;
char *dlocale;
verbose = 0;
while ((i = getopt(c, v, "v")) != -1) {
switch (i) {
case 'v':
verbose = 1; break;
case '?':
default:
usage();
exit(2);
}
}
c -= optind;
v += optind;
dlocale = setlocale(LC_ALL, "");
if (verbose)
printf("default locale = %s\n", dlocale ? dlocale : "''");
qsort(v, c, sizeof(char *), qsort_strcmp);
for (i = 0; i < c; i++) {
printf("%s ", v[i]);
}
printf("\n");
exit(0);
}
``The lyf so short, the craft so long to lerne.'' - Chaucer
Live Strong.
Chet Ramey, ITS, CWRU [EMAIL PROTECTED] http://tiswww.tis.case.edu/~chet/
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