On Friday 18 April 2008 14:02, Dave Rutherford wrote:
> Quotes or escapes in the output of the `` are input to the shell rather
> than shell syntax, so won't be interpreted. You just need to quote more.
>
> $ foo () { echo sony; echo apple; echo hewlett packard; }
>
> Now note the difference between:
>
> $ for w in "`foo`"; do echo $w; done
> sony apple hewlett packard
This assigns "sony", "apple", "hewlett" and "packard" to $w.
> $ for w in `foo`; do echo "$w"; done
> sony
> apple
> hewlett
> packard
Same as above, but $w is quoted (which does not change anything in this
case).
> $ for w in "`foo`"; do echo "$w"; done
> sony
> apple
> hewlett packard
This assigns
"sony
apple
hewlett packard"
as a single value to $w. Note that the for loop is executed only once. This
is not what the OP wanted.
