printf -v doesn't allow array assignment

[Chris F.A. Johnson]

$ printf -v q[2] "%s" "$RANDOM"
bash: printf: `q[2]': not a valid identifier


    I know I can work around it with a temporary variable, but it
    would be nice if it could be done in a single step.


--
   Chris F.A. Johnson                      <http://cfaj.freeshell.org>
   ===================================================================
   Author:
   Shell Scripting Recipes: A Problem-Solution Approach (2005, Apress)