monoped wrote:
>
> Am 29.05.2010 01:04, schrieb pikta:
>>
>> Hi all,
>> I'm just a beginer and I got stucked .... I'm trying to create multiple
>> array with variable in array's name. I would expect to have 3 arrays and
>> each of them would contain 3 elements like array1=(a b c) array2=(a b c
>> )
>> array3=(a b c) ; what means that first element of array1[0]="a" and for
>> example third element of array3[2]="c". This is the way how I do it :
>>
>> for (( n=1; n<4; n++ ))
>> do
>> array$n=(a b c)
>> done
>>
>> ...but there is syntax error....
>
> That's because array$n isn't a valid name. Use eval:
>
> eval "array$n=(a b c)"
>
> Bernd
>
> --
> Bernd Eggink
> http://sudrala.de
>
>
>
Hi, thanks a lot for hint, it works as expected !!!! (I tried to give you 5
stars but somehow there are only 3 and I can not chacge it ...; but thanks
a lot again!)
--
View this message in context:
http://old.nabble.com/create-array-in-loop-with-variable-in-array%27s-name-tp28712785p28723207.html
Sent from the Gnu - Bash mailing list archive at Nabble.com.
