On Sun, 26 Sep 2010, Christopher Roy Bratusek wrote:

btw. How can I remove the last arguement ${!#} ?

I tried args=${@:-${!#}} but that won't work.

args=( "$@" )
unset args[$#-1]
set -- "${ar...@]}"

--
   Chris F.A. Johnson, <http://cfajohnson.com>
   Author:
   Pro Bash Programming: Scripting the GNU/Linux Shell (2009, Apress)
   Shell Scripting Recipes: A Problem-Solution Approach (2005, Apress)

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