Bruce Dawson wrote:
> Chris Down pointed that out. My loop now looks like this -- portable (I
> believe) and fast:
>
> BashCount() {
> for (( i = $1 ; i > 0 ; i-- )); do
> :
> done
> echo Just did $1 iterations using bash math
> }
----
To do the above, you'd want to pre-init
(I'd use i=${1:?"need start count"} in bash, but don't know if that is portable)so, assuming I know i is > 0: i=$1; while $((i-=1)); do :; done
