On Fri, Nov 28, 2014 at 1:07 PM, William Park <opengeome...@yahoo.ca> wrote:
> Hi all, > > I just noticed that BASH_ARGV contains commandline arguments in reverse. > That's because it's a stack. According the bash manual: "The final parameter of the last subroutine call is at the top of the stack; the first parameter of the initial call is at the bottom." > > $ cat > x.sh > #!/bin/sh > declare -p BASH_ARGV > ^D > > $ sh x.sh 1 2 3 4 5 > declare -a BASH_ARGV='([0]="5" [1]="4" [2]="3" [3]="2" [4]="1")' > -- > William > >
