On 07/19/2016 09:45 PM, Chet Ramey wrote: > On 7/19/16 7:15 PM, Dan Douglas wrote: >> Hi, I could reproduce this in all bash versions. >> >> bash -c 'set -x; until continue; do :; done; echo test1'; echo test2 >> + continue >> test2 >> >> I'm not actually sure whether this is supposed to work at all. Almost >> all shells do something strange when given continue in the first >> compound-list. E.g. ksh93 does like bash and exits, and zsh breaks >> out of the loop. > > It should probably print `test1'
That's what I figured. Playing around with this test the current bash continues an outer loop if levels=1 while the "normal" ones (dash/mksh) do so at levels=2. I suppose technically a script that before would have continued the n+1th nested loop will now be off by one. (Not too likely such a script exists or they would have noticed this.) $ { bash /dev/fd/9; echo; } 9<<\EOF set -x; n=-1 levels=1 let 1 2>/dev/null || let() { IFS=, command eval test '$(($*))' -ne 0; } until echo 1 let n+=1 && break do until echo 2; continue "$levels" do : done echo 3 done EOF + n=-1 + levels=1 + let 1 + echo 1 1 + let n+=1 + echo 2 2 + continue 1 + echo 1 1 + let n+=1 + break
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