On 28.7. 17:22, Chet Ramey wrote:
On 7/23/20 8:11 PM, Alexey Izbyshev wrote:
$ Z='a b'
$ A=(X=$Z)
$ declare -p A
declare -a A=([0]="X=a b")
It's an assignment statement in a context where assignment statements are
accepted (which is what makes it different from `echo X=$Z', for instance),
but the lack of a subscript on the lhs makes it a special case. I'll take a
look at the semantics here.
This is also a bit curious:
$ b=( [123]={a,b,c}x )
$ declare -p b
declare -a b=([0]="[123]=ax" [1]="[123]=bx" [2]="[123]=cx")
It does seem to have a subscript on the LHS, but it didn't work as one.
To be in line with a plain scalar assignment, the braces should probably
not be expanded here.
--
Ilkka Virta / itvi...@iki.fi
