On 1/9/21 12:22 AM, Oğuz wrote:
Here's another trivial side effect of implementing
unary minus using binary minus:
$ echo $((16#-10))
-10
Since `-' is an operator, this is not unary minus. It's the same as
$(( 16# - 10 )), which bash before version 5.1 helpfully (or not) treats
identically to $(( 16#0 - 10 )). Bash-5.1 requires at least one digit
after the base specification, so this is a syntax error.
$ echo $((-16#10))
-16
This is unary minus applied to an integer constant.
--
``The lyf so short, the craft so long to lerne.'' - Chaucer
``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, UTech, CWRU c...@case.edu http://tiswww.cwru.edu/~chet/
