14 Şubat 2021 Pazar tarihinde Dale R. Worley <wor...@alum.mit.edu> yazdı:
> Before we worry about what to change, I want to note that the original > example is syntactically incorrect. The example is > > $ bash -c ': $(case x in x) esac)' > > But the manual page makes it clear that each case must be ended with > ";;". `;;' is optional for the last case item. > > case word in [ [(] pattern [ | pattern ] ... ) list ;; ] ... esac > > Now, I haven't investigated what cleverness Bash uses, but all the cases > I've tested that conform to the case syntax are handled correctly inside > this $(...): > > $ bash -c ': $( case x in x) : ;; esac )' > $ bash -c ': $( case x in x) true ;; esac )' > $ bash -c ': $( case x in (x) true ;; esac )' > > It even works with the degenerate case where there are no coices, though > writing it is hard because "esac" is a keyword: > > $ bash -c ': $( case x in > more> esac )' `case x in esac' (without the linebreak) works fine outside the command substitution. > This is with an old version, 4.2.53(1). > > Dale > -- Oğuz
