Hi,
I have encountered an issue when running some bash code from 4.3 that
behave in an unexpected way on 4.4 or 5 ... I've managed to pinpoint the
exact issue on my end.
Here is the code:
## ----------------
trap -- 'echo bar' EXIT
(
echo -n 'Subshell TRAP EXIT: '
trap -p EXIT
echo
)
echo main shell
##----------------
Runnning this will give the same output on bash 4.4 and 5:
## ---- BEGIN OUTPUT
Subshell TRAP EXIT: trap -- 'echo bar' EXIT
main shell
bar
## ---- END OUTPUT
But will give this output on bash 4.3:
## ---- BEGIN OUTPUT
Subshell TRAP EXIT:
main shell
bar
## ---- END OUTPUT
We notice 2 important point:
- Bash >4.3 trap's is displaying parent shell's EXIT trap, while
4.3 is not displaying it.
- None of them will execute any trap at the end of the subshell.
In 4.3, this makes sense to me. EXIT trap is not available and not executed.
In >4.3, I don't understand: 'trap -p' is displaying a trap that is not
really enabled ?
Notice that we can set an EXIT trap in the subshell, and then all bash
version will display AND execute the trap at the end of the subshell.
Which seems totally okay to me.
Is this strange behavior about bash >4.3 being able to display EXIT
trap, but won't use them is expected ? I'd be happy to know about the
rationale behind this if this is expected.
Many thanks,
Valentin Lab
PS: note that I found some other 'report' of that behavior here:
https://unix.stackexchange.com/questions/282722#answer-374269
