On 8/14/21 8:45 PM, Hunter Wittenborn wrote:
> Hi,
>
>
>
> I was doing some testing for some additions to a rather big Bash script I'm
> working on, and the following code kept failing whenever I attempted to run
> it:
>
>
>
> "
>
> variable="hello"
>
>
>
> declare -g "${variable}"=("world" "me")
Here's the answer I gave on help-bash:
It's a syntax error. There is an unquoted operator (`(') where the grammar
does not allow it.
`declare' does allow compound array assignment statements as arguments, and
the parser accommodates this as long as two conditions hold: the parser can
detect that the first word of a simple command is `declare' and the
argument is a valid assignment statement. In this case, the second fails,
since `"${variable}"' is not a valid shell identifier. That renders the
argument not a valid assignment statement.
--
``The lyf so short, the craft so long to lerne.'' - Chaucer
``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, UTech, CWRU c...@case.edu http://tiswww.cwru.edu/~chet/
