On 5/24/24 1:43 AM, Oğuz wrote:
While you're at it take a look at this too:true; for (( ; $? == 0; ${ ! break;} )); do uname; done
The arithmetic for command should probably check for breaking after it
evaluates the loop test. You have to admit this is not something people
are going to write as a matter of course.
--
``The lyf so short, the craft so long to lerne.'' - Chaucer
``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, UTech, CWRU c...@case.edu http://tiswww.cwru.edu/~chet/
