On Tue, 28 Oct 2025, 22:00 Andreas Schwab, <[email protected]> wrote: > Where is the second writev coming from? "echo 60" should output > $'60\n', and nothing else. >
As I noted before, the write is truncated, from 3 down to 2 bytes ("60"),
so libc (musl) is obligated to try again to write the 1 remaining byte
("\n").
-Martin
