The Wanderer wrote:
> What I was doing at the time, so far as I remember, was:
>
> for i in `ls path/to/directory1/ path/to/directory2/` ; do ls -l $i &&
> <complex operation I don't care to reproduce here> $i ; done
>
> but that didn't work because the filename printed by the subshell did
> not exist in the present directory.
Would this have worked there? I think it is basically the same
thing. But avoids the extra ls process and uses the shell directly
to list the directory.
for i in path/to/directory1/* path/to/directory2/* ; do
ls -l $i && <complex operation> $i
done
> If I were attempting to find in the hierarchy beginning at the curent
> directory, that would be fine. However, it is far more common for me to
> want to find in some hierarchy other than the one I'm currently at the
> top of,
How about this?
find $PWD/foo/* $PWD/bar/*
Or:
find $PWD/{foo,bar}/*
Bob
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