Hi Anreas / Eric, > Erik Auerswald <auers...@unix-ag.uni-kl.de> writes: > > >> Hi Wasim, >> >> On Sun, Mar 01, 2009 at 08:09:43PM +0530, Wasim Akram S.N. wrote: >> >>> Hi, >>> I don't know whether the following is really a bug. >>> ... >>> wa...@wasim:~/temp$ sort -g -k1,3 -t \t a >>> >> This tells sort to regard the first three fields as one key. I think >> you need something like "sort -g -k1,1 -k2,2 -k3,3 -t \t a" which uses >> the three fields as three keys. >> > > This won't work either since the separator 't' does not occur in the > input. If you want a TAB character as a separator (assuming there are > really TABs between the fields in the input) you need to pass a literal > TAB as the argument to -t. With bash you can do that with -t $'\t'. > > Andreas. > >
Based on your suggestion, I tried this and now its working. wa...@wasim:~/temp$ sort -g -k1,1 -k2,2 -k3,3 -k4,4 -t $'\t' a 1 1 1 2 2 2 4 1 1 4 2 2 4 10 10 4 100 100 10 10 10 100 10 1 200 1 1000 200 2 10 200 20 100 wa...@wasim:~/temp$ Thanks a ton Regards, Wasim Akram _______________________________________________ Bug-coreutils mailing list Bug-coreutils@gnu.org http://lists.gnu.org/mailman/listinfo/bug-coreutils
