(info "(coreutils) seq invocation")
... seq [OPTION]... FIRST INCREMENT LAST
`seq' prints the numbers from FIRST to LAST by INCREMENT. By
default, each number is printed on a separate line. When INCREMENT is
not specified, it defaults to `1', even when FIRST is larger than LAST.
FIRST also defaults to `1'. So `seq 1' prints `1', but `seq 0' and
`seq 10 5' produce no output. Floating-point numbers may be specified.
*Note Floating point::.
OK but I think you forgot to mention cases like
$ seq 0 5 17
Will the last value printed be
15, 17, or 20?
the user wonders. Hard to tell from the man/info page.
