"Shivageetha C" <[EMAIL PROTECTED]> wrote:
| I am a software engineer working for Novell.
|
| Interduction to the problem:
| There is a file, with the group owner for the file being systemtest, if I execute ls
|-l for the file, then the group name will be trunkated (i.e. only the first 8
|characters will be displyed)
|
| The output:
| # ls -l test_file
| -rw-r--r-- 1 admin systemte 0 May 31 16:52 test_file
|
| Can you please let me know how to get the complete group name?
It's not possible with ls from fileutils-4.1, but it will be
fixed for the next release.
You can use GNU find to get the full username and/or group:
find your-file-or-directory -printf '%u %g\n'
Here's a patch for ls:
Index: ls.c
===================================================================
RCS file: /fetish/fileutils/src/ls.c,v
retrieving revision 1.264
diff -u -p -r1.264 ls.c
--- ls.c 2001/05/24 20:06:21 1.264
+++ ls.c 2001/05/25 20:56:13
@@ -2610,7 +2610,7 @@ print_long_format (const struct fileinfo
{
char *user_name = (numeric_ids ? NULL : getuser (f->stat.st_uid));
if (user_name)
- sprintf (p, "%-8.8s ", user_name);
+ sprintf (p, "%-8s ", user_name);
else
sprintf (p, "%-8lu ", (unsigned long) f->stat.st_uid);
p += strlen (p);
@@ -2620,7 +2620,7 @@ print_long_format (const struct fileinfo
{
char *group_name = (numeric_ids ? NULL : getgroup (f->stat.st_gid));
if (group_name)
- sprintf (p, "%-8.8s ", group_name);
+ sprintf (p, "%-8s ", group_name);
else
sprintf (p, "%-8lu ", (unsigned long) f->stat.st_gid);
p += strlen (p);
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