On 06/11/2010 03:47 PM, Peng Yu wrote: > Hello, > > I want to find all the directories that do not have any file in them > (there can be directories in them). Could you show me how to do it?
Interesting challenge. First, I created a test hierarchy:
$ ls -RF
.:
a/ b/ d/
./a:
./b:
c/ f
./b/c:
./d:
e/
./d/e:
g
Then, I used this. It may not be the most efficient, but it works. The
idea is to have find list directories, then to use -exec to have the
shell determine if the directory contains any non-directory children.
You are guaranteed that .* will resolve (each directory contains . and
..), but you have to special case * in case it didn't match. The end
result is a bit long, but meets your requirements.
$ find -type d -exec sh -c 'cd -- "$1" && \
for f in * .*; do test "$f" = "*" && test ! -e "$f" && continue; \
test -d "$f" || exit 1; done' sh {} \; -print
.
./a
./b/c
./d
It correctly discarded ./b (because of ./b/f) and ./d/e (because of
./d/e/g) while still including ./b/c (a child of the discarded ./b) and
./d (a parent of the discarded ./d/e); if that's not exactly what you
wanted, then you need to tweak your question slightly.
--
Eric Blake [email protected] +1-801-349-2682
Libvirt virtualization library http://libvirt.org
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