> If the memory you are pointing to, points to a char then do "p (char *)ptr"
> else cast the pointer to the specific type it points to. (void *) is just a
> pointer to something, so gdb does not know how to interpret the value the
> pointer points to.
The other option is the ``x'' command.
x/4b 0xc0c8ab0
will print that as 4 bytes
> -----Original Message-----
> From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]]
> Sent: Thursday, November 29, 2001 8:48 AM
> To: [EMAIL PROTECTED]
> Subject: To see a memory location using gdb
>
>
> Hi every body,
> I was looking for a GDB news group and i can found only this one.
> There is one void * ptr. And if i want to see the memory content what
> can i do? If i try print ptr, then i can see the memory address
> (suppose it is 0xc0c8ab0). Please help.
>
> Mem
>
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