Bruno Haible <[EMAIL PROTECTED]> writes: > The purpose of the test is not to create a signalling NaN (despite the > comment saying so). The purpose is to create a binary representation of > a NaN that is not one of the "usual" NaNs.
Even if that were true (which obviously isn't), it still fails to do that. When run on the m68k extended real format it creates a bit representation that only differes in a padding bit, which is completely ignored anyway. This shows that the test in the current form is useless. Andreas. -- Andreas Schwab, SuSE Labs, [EMAIL PROTECTED] SuSE Linux Products GmbH, Maxfeldstraße 5, 90409 Nürnberg, Germany PGP key fingerprint = 58CA 54C7 6D53 942B 1756 01D3 44D5 214B 8276 4ED5 "And now for something completely different."
