BTW,
Replacing the 1 with a variable, "b" in this case, DOES compile and completely
changes the behavior which is worse since you there is no compile error.
a += - -b;
indent transforms it to:
a += --b;
Which has a different outcome.
int main (int argc, void *argv[])
{
int a = 20, b = 5;
a += - -b;
printf ("a: %d, b: %d\n", a, b);
return 0;
}
Outputs:
a: 25, b: 5
While
int main (int argc, void *argv[])
{
int a = 20, b = 5;
a += --b;
printf ("a: %d, b: %d\n", a, b);
return 0;
}
Outputs:
a: 24, b: 4
smanders
-----Original Message-----
From: [email protected]
[mailto:[email protected]] On Behalf Of Santiago Vila
Sent: Friday, May 08, 2009 5:52 AM
To: [email protected]
Cc: [email protected]; Xavier Bestel
Subject: Bug#527450: indent breaks C code ! (fwd)
Hello.
I received this from the Debian bug system.
[ Please keep the Cc: lines when replying. Thanks ].
---------- Forwarded message ----------
From: Xavier Bestel <[email protected]>
To: Debian Bug Tracking System <[email protected]>
Date: Thu, 07 May 2009 17:39:32 +0200
Subject: Bug#527450: indent breaks C code !
Package: indent
Version: 2.2.10-1
Severity: important
Hi,
when feeding this line:
a += - -1;
indent transforms it to:
a += --1;
which hasn't the same meaning at all (instead of a unary minus on a negative
constant, it's a predecrementation of a constant) and in this example isn't
even legal C code.
It's quite a serious issue.
Thanks,
Xav
[...]
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