> 1. "foo" is simple variable. > so result have to be 100 but is 200 > > foo := > val := 100 > > all : foo += $(val) > all : > @echo foo : $(foo) > > val := 200 > > result is : 200
Yes, the result will become 200 because foo is not expanded until it is usead at the line "@echo foo : $(foo)". At that time, before building "all" the entire Makefile will have been read and val was assigned to 200 at the last line in the Makefile. > ------------------------------------------------------- > > 2. If i change '+=' operator to ':=' then result is 100 > > foo := > val := 100 > > all : foo := $(val) > all : > @echo foo : $(foo) > > val := 200 > > result is : 100 > ---------------------------------- Yes, because ":=" unlike "=" and "+=" is expanded at that very line. regards Henrik _______________________________________________ Bug-make mailing list Bug-make@gnu.org https://lists.gnu.org/mailman/listinfo/bug-make
