On 5/8/07, Gopi Krishna Komanduri <[EMAIL PROTECTED]> wrote: > I agreed for your explanation. But , consider a code for copy > constructor or assignment operator overloading methods. Those will be > provided irrespective of whether we create objects or not. Am I correct? If > so , in side the code , the implementation wil be with "this" pointer > itself na! .. Even if we think like the assignment for this pointer will be > done by creation of object(passing &obj as hidden parameter and catching this > address into this pointer and using it , ) even in this xcase also .. some > memory will be occupied for formal parameters and that included the size of > this pointer also na! > Please correct me where I missed the track!
Parameters for a function call are not stored in the object. They are allocated outside of the object. I don't understand what's the problem. -- Tamas Marki
