Right :)

2009/4/11 Paul Herring <[email protected]>

>
>
> On Fri, Apr 10, 2009 at 7:41 PM, Christopher Coale 
> <[email protected]<chris95219%40gmail.com>>
> wrote:
> > I'm not sure if you are just using that code to make a point, but that
> > won't work. You are getting the size of the pointer (which is usually 4
> > or 8 bytes), and dividing that by the size of the type.
>
> That's exactly the point they were originally making - i.e. it doesn't
> work because it's a pointer to an array being passed in, not the
> original array itself.
>
> --
> PJH
>
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>  
>


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