A way to help determine how you want the following scenario to play out is to surround the piece of code you want to be sure is enacted on first with ( ).
For example... int b = a / (++a); This will remove all doubt as to what will happen. --- On Thu, 7/16/09, Paul Herring <[email protected]> wrote: From: Paul Herring <[email protected]> Subject: Re: [c-prog] I am not agree with u. To: [email protected] Date: Thursday, July 16, 2009, 10:43 AM On Wed, Jul 15, 2009 at 8:38 AM, Nayera Khan<[email protected]> wrote: > How it could be? is it possible after initializing a=5 ,6 could divided by 6 , > It could possible after dividing a by ++a,a will be six Given int a = 5; and int b = a / ++a; You don't know (and should never assume) whether the compiler will look at: o the 'a' first (and the '++a' second) or o the '++a' first (and the 'a' second) If it looks at the 'a' first, it will arrive at: 5/6 If it looks at the '++a' first it will arrive at: 6/6 Since this is integer arithmetic, the first returns 0 and the second returns 1. Since this is C (or C++) and the compiler is allowed to choose which of 'a' or '++a' is looked at first, the answer is indeterminable, and thus the whole expression (and ones like it) should not be used in C or C++ since you can not guarantee the answer. What your other favourite language does with such expressions is irrelevant here. -- PJH http://shabbleland.myminicity.com/com http://www.chavgangs.com/register.php?referer=9375 ------------------------------------ To unsubscribe, send a blank message to <mailto:[email protected]>.Yahoo! Groups Links [Non-text portions of this message have been removed]
