[c-prog] Re: moving average problem

[billcu34]

--- In c-prog@yahoogroups.com, Christopher Coale <chris95...@...> wrote:
>
> Bill Cunningham wrote:
> >  
> >
> > I want to write a function to take so many numbers (doubles) and divide
> > their total number (int) and get a arithmetic average. This probably 
> > sounds
> > simple to all the C pros here but here's my parameter.
> >
> > double Sma (double *, int);
> >
> > That's the prototype I have. The thing is I want to enter as many 
> > number as
> > I want, two decimals to the right of the . or %.2f\n as printf would 
> > put it.
> > I don't want a buffer overflow but I can take the numbers I put in a 
> > divid
> > them by the second parameter. To make things more complex I could write
> > double Sma (double *) and let the body of the function see how many 
> > args are
> > entered. For this the for or while statements are going to be needed 
> > right?
> >
> > Bill
> >
> > 
> I'm confused as to what the problem is.
> 
> double Sma(double *ds, int size)
> {
>     double res = 0;
>     for (int i = 0; i < size; i++)
>        res += ds[i];
> 
>     return ds / (double)size;
> }

   I have lost some precision with this code. But I would like to take it a 
step farther.

double Sma(double *);

Is my prototype. Instead of entering the value to divide by how can I get the 
program to count the number of numbers entered, can I get the code to count 
this itself?

Bill