Hi dear, Armstrong Number : 153 = (1)3 + (5)3 + (3)3 So you have to enter 153 that display the armstrong number. Enjoy Have a nice time.
--- On Fri, 23/10/09, Rick <[email protected]> wrote: From: Rick <[email protected]> Subject: Re: [c-prog] Prog help! To: [email protected] Date: Friday, 23 October, 2009, 10:59 PM At 10/22/2009 08:02 AM, you wrote: ># include <iostream.h> ># include <conio.h> ># include <math.h> > void main () >{ clrscr(); > int a,b=0,sum=0; > long int n; > cout<<"ENter the NO. : "; > cin>>n; > for(;n>0;) >//counts the digits > { a=n%10; > n=n/10; > b++; > } > for(;n>0;) > { a=n%10; > sum=sum+pow( a,b); > n=n/10; > } > if(sum==n) > { cout<<"IT IS AN ARMSTRONG NUMBER..."; > getch(); > } > else > { cout<<"IT IS NOT AN ARMSTRONG NUMBER..."; > getch(); > } >} > > >-- in this code every time the ans is "IT IS AN ARM STRONG NUMBER....' why >is this so i m having problem in making this program with the help of class >can i get some help >shruti dixit You have several problems. The biggest problem is probably that you haven't defined you algorithm correctly. I looked up Armstrong numbers (here: http://www.cs. mtu.edu/~ shene/COURSES/ cs201/NOTES/ chap04/arms. html) and it says "An Armstrong number is a number such that the sum of its digits raised to the third power is equal to the number itself". You are raising the digits to the number of digits in the number, not by 3. (BTW: I don't believe 153 is a valid Armstrong number as stated on the web site). I put the computation into a function -- check below. ~Rick // An Armstrong number is a number such that the sum of its digits // raised to the third power is equal to the number itself. // For example, 371 is an Armstrong number, since 3**3 + 7**3 + 1**3 = 371. #include <cstdlib> #include <iomanip> #include <iostream> using namespace std; # include <math.h> bool isArmstrong( long int number) { long int digit; long int value; long int sum = 0; // Compute the sum value = number; // Save the original value while (value > 0) { digit = (value % 10); sum += (long int)pow((double) digit, 3); value /= 10; } return (sum == number); } int main(int argc, char *argv[]) { long int number; for (number = 0; number < 1000; ++number) { // cout << "Enter the number: "; // cin >> number; if (isArmstrong( number)) { cout << setw(5) << number << " IS AN ARMSTRONG NUMBER.\n"; } else { // cout << setw(5) << number << " IS NOT AN ARMSTRONG NUMBER.\n"; } } return EXIT_SUCCESS; } [Non-text portions of this message have been removed] Keep up with people you care about with Yahoo! India Mail. Learn how. http://in.overview.mail.yahoo.com/connectmore [Non-text portions of this message have been removed]
