manishpchawda wrote:
>
> [mod-- This gets discussed ad-nauseum. The behaviour is undefined
> since the code modifies x (and y) twice between sequence points.
> <http://c-faq.com/expr/seqpoints.html
> <http://c-faq.com/expr/seqpoints.html>> --mod PN]
>
> Hi,
>
> I am not able to understand the output of:
>
> unsigned char x;
> x = 300;
> printf("%d",x);
>
> int x,y;
> x = 5;
> y = 10;
> printf("%d\t%d\t%d\t%d\t",x++,y++,++x,++y);
>
> Regards,
>
> Manish
>
>
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What's your compiler?
gcc gives this output,
#include <stdio.h>
int main(void)
{
unsigned char x;
x = 300;
printf("%d", x);
return 0;
}
output> 44
? unsigned char gets truncated to 44 as 300 - 256 = 44
#include <stdio.h>
int main(void)
{
int x,y;
x=5;
y=10;
printf("%d\t%d\t%d\t%d\t",x++,y++,++x,++y);
return 0;
}
output>> 6 11 7 12
? x++, y++, ++x, ++y behave same here. so its just that x and y get
incremented.
Cheers,
Vishva
