Asad,
"But when i==3 and ++m+1 is executed then why the value of m is incremented by
1 only?
(++m+1) This should increment the value of m by 2 :("
m is incremented by 1 for sure and it's easy to see why.
When (i==3 ? ++m+1 : m--) is evaluated and i equals 3 the result is:
1. m incremented by 1 first (because the prefix increment operator has
higher precedence over the addition operator;
2. then 1 is added to m's new value and cout'ed, but m doesn't change at all.
One thing is ++m+1, another m=++m+1 (yes, in this case m's final value is
greater than m's initial value by 2: m's initial value is first incremented by
1, then 1 is added to the result and finally the result is stored back to m.
Should you really add 2 to m when i equals 3, make (i==3 ? m=++m+1 : m--).
No problem placing an assignment inside the ternary conditional if you don't
know: it has/returns the value of the assignment.
To boot, and since the = operator associates from right to left, it's
possible an assigment like this: i=j=k=0.
Best,
Geraldo
--- In [email protected], Asad Abbas <cyberstuden...@...> wrote:
>
> Consider the following code
>
> main()
> {
> for(int i=1,m=9;++i< 4;)
> for(int j=1;j<4;j++)
> for (int k=1;k++<4;)
> cout<<(i==3? ++m+1:m-- );
> getch();
> }
>
> Its output: (on Dev C++)
>
> 9876543212345678910
>
> ---
>
> I could not understand when 'i' is not equal to 3 'm--' is executed so value
> of m is decremented by '1' (thats right)
> But when i==3 and ++m+1 is executed then why the value of m is incremented by
> 1 only?
> (++m+1) This should increment the value of m by 2 :(
>
> ---
>
> Where am i Wrong?
>
> Thanx in advance!
>
> Regards!
> Asad Abbas
> Pakistan
> ---
>
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