Have you got prototype.js loaded?
If you use mozilla, the firebug extension is quite useful for debugging
ajax problems, you can configure it to tell you (amongst other things)
js errors, to show remote requests and their responses.
Incidentally, does the results for getSchoolOrganizations change?
If it doesn´t
you don´t need the remote call, you can echo the output of
$this->requestAction with the same url
If it does change (assume that´s the intention)
You are going to need a means of passing/determining the
$schoolListId (or other parameters). For that you will possibly need to
specify a "with" parameter to the call.*
HTH,
AD7six
* Meaning something like:
echo $ajax->remoteFunction(array('update'=>'menu',
'url'=>'/organizations_list/getSchoolOrganizations', 'with' =>
"Form.serialize('SchoolFormId')"));
Then check $this->controller->data in the controller method receiving
the ajax call
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