i had to use backslashes...^^ it works now

thanks for your time guys..appreciate it :)

On 30 Okt., 22:10, "flo.kl...@googlemail.com"
<flo.kl...@googlemail.com> wrote:
> I always use “ to encapsulate the string I want to echo. Then you can use ' 
> within and it will be echoed as well.
> A short example:
> echo “<div id='myId'>“.$array['fieldName'].“</div>“;
>
> -flosky
>
> Tomfox Wiranata <tomfox.wiran...@gmail.com> schrieb:
>
> lets say i wanna go with echo, how do i need to quote or escape the
> current code, that it works?
> cause i have no idea how to implement the value thing..
>
> thanks..appreciate it
>
> On 30 Okt., 05:52, Ryan Schmidt <google-2...@ryandesign.com> wrote:
>
>
>
>
>
>
>
>
>
> > On Oct 29, 2011, at 10:56, Tomfox Wiranata wrote:
>
> > > echo '<div id="showGoogleMap" onclick="showGoogleMap('.$all['id'].','.
> > > $all['BooksUser']['latitude'].',
> > > '.$all['BooksUser']['longitude'].','.$all['title'].')"
> > > style="float:right;cursor:pointer;">'.$html->image("icons/map.png",
> > > array("alt" => "Google Map anzeigen")).'</div>';
>
> > [snip]
>
> > > now when I hit
> > > the icon to open the map, firebug says this:
> > >_____________________________________________
>
> > > missing ) after argument list
> > > showGoogleMap(207,47.378824,8.548737,Tag Heuer Carrera Chronograph)
>
> > As you see from the error message (or by viewing source on the page), your 
> > PHP code generated the following HTML code:
>
> > <div id="showGoogleMap onclick="showGoogleMap(207,47.378824,8.548737,Tag 
> > Heuer Carrera Chronograph)" style="float:right;cursor:pointer;">...</div>
>
> > What got generated inside the onclick attribute is not valid JavaScript 
> > code, because the title string is not quoted or escaped properly. You 
> > probably want to use JsHelper::value($all['title']) instead of just echoing 
> > $all['title'] directly.
>
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