You can use Containable behavior and write something like this:
$Office->find('all', array(
...
'contain' => array(//or 'contains' -> check manual ;)
'Company' => array('fields' => array('name')),
'Person' => array(
'fields' => array('mail'),
'OfficePersonTask' => array( )
'Office' => array('fields' => 'name'),
'Task' => array('fields' => 'name'),
),
),
...
));
Or try setting the fields names in $hasMany, $hasOne, etc array
http://book.cakephp.org/2.0/en/models/associations-linking-models-together.html#hasone
On Tuesday, July 31, 2012 12:16:38 PM UTC+2, Mariano C. wrote:
>
> In CakePHP 2.1 I have prepared a Json webservice. This is an excerpt of
> what I get:
>
> {
>> Offices:[
>> {
>> Office:{
>> id:"1",
>> Company:{
>> id:"1",
>> name:"ABC Software"
>> }
>> },
>> Person:{
>> mail:"s...@saass.it",
>> OfficePersonTask:[
>> {
>> office_id:"1",
>> person_id:"1",
>> task_id:"1"
>> }
>> ]
>> }
>> }
>> ]
>> }
>
>
> What I want is the possibility to show only some field from relative
> database, so the method that query the database have `$options['fields']`
> properly setting, so if I want to show person's mail I write:
>
> $options['fields'] = array("Person.mail");
>
>
> but what if I want to show company's id or company's name whice is one
> level deeper?
>
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