I don't think that Session is accessible from Model. But CMIIW.
If the above is true, then you'll need to move the matching logic into the
controller. You can use the beforeFilter callback function on the active
Controller to validate accessible shops.
On 12/22/06, kjohn <[EMAIL PROTECTED]> wrote:
Hi all,
I am a newbie to cakephp & php OO..
I am confused how best to handle the following case:
- Shop hasAndBelongsToMany Users (who can edit the Shop details).
- Now, in the shops view page (say shops/view/2), how to check that
the currently logged in user can edit the shop (2) details?
I was thinking of adding the following to the shop.php model:
var $hasAndBelongsToMany = array('User' =>
array('className' => 'User',
'joinTable' => 'users_shops',
'conditions' => 'User.id = '.
$this->Session->read('User.id'),
)
);
If this works, I could just read the $shop['User'] to check if the
current user can edit the Shop details. But it doesnt seem to work.
Any better way to get this working?
TIA
john
>
--
Adrian Godong
[EMAIL PROTECTED]
Microsoft Student Ambassador
--~--~---------~--~----~------------~-------~--~----~
You received this message because you are subscribed to the Google Groups "Cake
PHP" group.
To post to this group, send email to cake-php@googlegroups.com
To unsubscribe from this group, send email to [EMAIL PROTECTED]
For more options, visit this group at
http://groups.google.com/group/cake-php?hl=en
-~----------~----~----~----~------~----~------~--~---
