It doesn't work right away, but something like this does work:
In my player model:
function afterFind($results) {
foreach ($results as $key => $val) {
if( isset( $val['Player'] ) ) {
$results[$key]['Player']['full_name'] =
$val['Player']['first_name'] . ' ' . $val['Player']
['last_name'];
}
}
return $results;
}
and then you can set:
var $displayField = 'full_name';
On May 31, 10:49 am, gentleJuggernaut <[EMAIL PROTECTED]> wrote:
> When using the Scaffolding and declaring a $displayField in a foreign
> model, is there a way to specify two fields (i.e. var $displayField =
> 'first_name' . 'last_name';)?
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