Well, for anybody in a similar situation, I have solved this problem.
It seems as though the second code only works like so:
<?php for ($i=1; $i<=$div_total; $i++) { ?>
<?php echo $ajax->div($div_id . $i,
array('style'=>'display:inline')); ?>test content<?php echo $i; ?><?
php echo $ajax->divEnd($div_id . $i);?>
<?php } ?>
In other words, you cannot join the $ajax->div echo statement with
another echo statement; it needs to stand on its own. Very strange.
On Sep 10, 1:55 am, Anthony <[EMAIL PROTECTED]> wrote:
> Well, it seems as though Cake is being picky...
>
> In my view which is rendered for the AJAX output, if I have this code,
> it works:
>
> <?php echo $ajax->div('id1', array('style'=>'display:inline')); ?>
> test content 1
> <?php echo $ajax->divEnd('id1'); ?>
> <?php echo $ajax->div('id2', array('style'=>'display:inline')); ?>
> test content 2
> <?php echo $ajax->divEnd('id2'); ?>
>
> However, the following code does not:
>
> <?php for ($i=1; $i<=$div_total; $i++) {
> echo $ajax->div($div_id . $i, array('style'=>'display:inline')) .
> 'test content' . $i . $ajax->divEnd($div_id . $i);
>
> } ?>
>
> Theoretically, the second code should output exactly the same
> information as the first one. And if I go directly to the rendered
> view in my browser, it does. However, when it comes to using it in an
> AJAX environment, the first code outputs 'test content #' in each div
> while the second code outputs a blank string in each div - ''.
>
> Thoughts?
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