It does not work...
I have a SQL Error.
Here it is :
*Notice*: Undefined offset: 0 in
*Z:\dev\frameworks\cake\cake\libs\model\datasources\dbo_source.php* on
line *1388*
*Notice*: Undefined offset: 0 in
*Z:\dev\frameworks\cake\cake\libs\model\datasources\dbo_source.php* on
line *1390*
*Notice*: Undefined offset: 0 in
*Z:\dev\frameworks\cake\cake\libs\model\datasources\dbo_source.php* on
line *1393*
*Notice*: Undefined offset: 0 in
*Z:\dev\frameworks\cake\cake\libs\model\datasources\dbo_source.php* on
line *1397*
*Notice*: Undefined offset: 0 in
*Z:\dev\frameworks\cake\cake\libs\model\datasources\dbo_source.php* on
line *1400*
*Notice*: Undefined offset: 1 in
*Z:\dev\frameworks\cake\cake\libs\model\datasources\dbo_source.php* on
line *1390*
*Notice*: Undefined offset: 1 in
*Z:\dev\frameworks\cake\cake\libs\model\datasources\dbo_source.php* on
line *1393*
*Notice*: Undefined offset: 1 in
*Z:\dev\frameworks\cake\cake\libs\model\datasources\dbo_source.php* on
line *1397*
*Notice*: Undefined offset: 1 in
*Z:\dev\frameworks\cake\cake\libs\model\datasources\dbo_source.php* on
line *1400*
*Notice*: Array to string conversion in
*Z:\dev\frameworks\cake\cake\libs\model\datasources\dbo_source.php* on
line *1149*
*Query:* SELECT Array, duedate ASC, `Task`. FROM `tasks` AS `Task` LEFT
JOIN `users` AS `User` ON (`Task`.`user_id` = `User`.`id`) LEFT JOIN
`users` AS `Assigned` ON (`Task`.`assigned_id` = `Assigned`.`id`) LEFT
JOIN `marks` AS `Mark` ON (`Task`.`mark_user_id` = `Mark`.`mark_id`)
LEFT JOIN `progresses` AS `Progress` ON (`Task`.`progress_id` =
`Progress`.`progress_id`) LEFT JOIN `priorities` AS `Priority` ON
(`Task`.`priority_id` = `Priority`.`priority_id`) WHERE all LIMIT 1
*Warning*: *SQL Error:* 1064: You have an error in your SQL syntax;
check the manual that corresponds to your MySQL server version for the
right syntax to use near 'ASC, `Task`. FROM `tasks` AS `Task` LEFT JOIN
`users` AS `User` ON (`Task`.`user' at line 1 in
*Z:\dev\frameworks\cake\cake\libs\model\datasources\dbo_source.php* on
line *440*
I try by changing your code regarding to the error but I still get a SQL
Error...
grigri wrote:
> Try this:
>
> $tasks = $this->Task->find('all', array(
> 'conditions' => array(
> 'or' => array(
> array('user_id' => $user_id),
> array('alternate_id' => $user_id, 'user_id' => '<> ' . $user_id)
> ),
> 'duedate' => date('Y-m-d')
> ),
> 'order' => 'duedate ASC'
> ));
>
> On May 16, 2:53 pm, Pierre MARCOURT <[EMAIL PROTECTED]> wrote:
>
>> Here are the requests I am doing :
>>
>> $tab1 = $this->Task->findAll('user_id = ' . $user_id . ' AND duedate =
>> "' . date('Y-m-d') . '"', null, 'duedate ASC');
>> $tab2 = $this->Task->findAll('alternate_id = ' . $user_id . ' AND
>> user_id != '.$user_id.' AND duedate = "' . date('Y-m-d') . '"', null,
>> 'duedate ASC');
>> $tasks = array_merge($tab1, $tab2);
>> $this->set('tasks', $tasks);
>>
>> I don't like that way, because I am using twice /findAll()/ on the same
>> table and for only one result at the end.
>> That's why I was wondering if there is a way to do it better.
>>
>> I think that your example is better than mine because you are doing a
>> simple query ($tmp) to get the ids (this query should not take too long)
>> and then the /findAll()/ query.
>> I don't like my way because, by using twice /findAll()/, my requests
>> could take too long for a lot of rows... And I don't see how to rewrite
>> it without using UNION because there is the condition user_id !=
>> '.$user_id.' in the 2nd one which is the contrary of 'user_id = ' .
>> $user_id . ' in the first one...
>>
>> Anyway, thanks for you help !
>>
>>
>>
>> grigri wrote:
>>
>>> In a word, no.
>>>
>>> In a UNION, MySQL does not return any table information with each
>>> column [since it can't, because a union can be from different tables],
>>> and cakephp's dbo_mysql class relies on this information to map the
>>> result rows to the originating model (think left joins).
>>>
>>> What exactly is the query you're trying to produce? There must be a
>>> way to rewrite it to not use a union (which are not usually that
>>> efficient anyway).
>>>
>>> If the union query you're creating is from the same table, you could
>>> always perform the union as a query(), but only return the row ids,
>>> then use Set::extract() on the result to get the ids into a flattened
>>> list, then call findAll with the id list:
>>>
>>> $tmp = $this->query('SELECT Product.id FROM [complicated sql] UNION
>>> SELECT Product.id FROM [complicated sql]');
>>> $ids = Set::extract($tmp, '{n}.0.id');
>>> $products = $this->findAll(array('Product.id' => $ids));
>>>
>>> hth
>>> grigri
>>>
>>> On May 16, 2:17 pm, Pierre MARCOURT <[EMAIL PROTECTED]> wrote:
>>>
>>>> Hi,
>>>>
>>>> I would like to make a MySQL request with an UNION but I can't find out
>>>> a way to do it by using CakePHP methods.
>>>> I looked at Google but it seems that the only way to do it is to make a
>>>> custom request by using /query()/.
>>>> But I don't want to do it that way because I need the recursive option
>>>> that we can have with /find()/ or /findAll()/.
>>>> So, to make it works, I am doing 2 different requests (by using
>>>> /findAll()/) and I merge the 2 results in a array().
>>>> To be honest, I don't like my idea at all.
>>>>
>>>> I would like to know if there is another way to do it better ?
>>>>
>>>> Thanks.
>>>>
>>>> --
>>>> *Pierre MARCOURT*
>>>>
>>>> *IT Department*
>>>> *CableOrganizer.com*
>>>> 5610 NW 12th Ave, suite 214
>>>> Fort Lauderdale, FL 33304
>>>>
>>>> Phone: 954-861-6310
>>>> Fax: 954-861-2001
>>>>
>> --
>> *Pierre MARCOURT*
>>
>> *IT Department*
>> *CableOrganizer.com*
>> 5610 NW 12th Ave, suite 214
>> Fort Lauderdale, FL 33304
>>
>> Phone: 954-861-6310
>> Fax: 954-861-2001
>>
> >
>
--
*Pierre MARCOURT*
*IT Department*
*CableOrganizer.com*
5610 NW 12th Ave, suite 214
Fort Lauderdale, FL 33304
Phone: 954-861-6310
Fax: 954-861-2001
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