For a pure javascript/ajax template, go here http://ajaxphp.packtpub.com/
and download the sample chapter http://ajaxphp.packtpub.com/1825_01_Final.pdf
This should give you a basic working xmlhttprequest that should be
easy to modify to do what you need.
On Oct 17, 11:57 am, bookme <[EMAIL PROTECTED]> wrote:
> Hi,
>
> I am using jquery for ajax in my application.. and was getting very
> good results using it.
>
> But when I was working on a registration page then this jquery is not
> providing me seamless effect.
>
> There is two select box - drop down
> 1 State
> 2 City
> when ever a user select a state correspondingly city comes in city
> drop down. jquery - ajax is working fine but it's taking time to
> displaying results.
>
> So I have to use simple ajax approach
>
> 1 Create a HTTP object : httpObject
>
> 2 open http connection
>
> httpObject.open("GET", url, true);
> httpObject.send(null);
> httpObject.onreadystatechange = setOutput;
>
> 3 getting response on httpObject.readyState == 4
>
> till now working fine but in next line creating problem
>
> top = httpObject.responseXML.getElementsByTagName("cities")[0];
>
> JavaScript Error : httpObject.responseXML has no properties ??
>
> I tested it using httpObject.responseText it's working fine.
> Also my controller is generating xml ..xml is showing in view source
> but i think it's not correct because View Genearted Source not showing
> xml instead of it showing HTML
>
> View Source is
> <?xml version='1.0' encoding='ISO-8859-1'?>
> <cities>
> <cityname><id>0</id><name>100</name></cityname>
> </cities>
>
> Is I am going on write track?
>
> How should I generate xml for this ajax request ..I have alraedy added
> Xml, RequestHandler everything but can not solve problem ?
>
> Thanks !!
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