if (isset($this->data['Genre']['id']) &&
is_array($this->data['Genre']['id']) && !in_array('51',
$this->data['Genre']['id']))
{
$this->data['Genre'][] = 51;
// or, array_push($this->data['Genre'], 51);
}
On Thu, Jan 22, 2009 at 8:28 PM, kai <k3ho...@gmail.com> wrote:
>
> In $this->data:
> [Genre] => Array
> (
> [id] => Array
> (
> [0] => 2
> [1] => 55
> )
>
> )
> In sql:
> WHERE `Genre_id` IN ('2', '55')
>
> Yeah, I want to add to their selection, not override it.
>
> On Jan 22, 5:21 pm, brian <bally.z...@gmail.com> wrote:
>> If a user "chooses a genre" what does the data look like? Before your
>> code does anything. Is it well formed?
>>
>> If you want to set ['Genre']['id'] to some value, what does the data
>> look like before that? It seems like you're trying to override the
>> user's selection, rather than add to it. Do you want to add ID=51 *in
>> addition* to whatever genre ID the user passes?
>>
>> On Thu, Jan 22, 2009 at 8:09 PM, kai <k3ho...@gmail.com> wrote:
>>
>> > When a user submits a form I'm hoping to apply some logic to their
>> > choice. The form takes user input and translates their selection into
>> > conditions to use in a query. One part of the selection is the choice
>> > to choose a genre. I'm hoping to say something like, if user chooses
>> > one genre or more then also add 'this genre' to their query. I tried
>> > something like:
>>
>> > if (!empty($this->data['Genre']['id']) and count($this->data['Genre']
>> > ['id']) > 0) {
>> > $this->data['Genre']['id'] = 51;
>> > }
>>
>> > but have found that $this->data['Genre']['id'] = 51; does nothing. How
>> > can i force genre 51 to become part of the query if the user chooses
>> > at least one genre?
> >
>
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