Thanks for the reply, I've misunderstood the concept of model, which is only the schema layer. I wanted the model to act as controller...
After reviewing the relations, I've added some containable and now I have acheived the result the proper MVC way. Flipflops pisze: > Hi Faza > > I don't think it is a problem with using ClassRegistry::init inside > another model as do exactly what you are trying to do quite a lot. > (e.g. $link_data = ClassRegistry::init('Link')->get_shared_links();) > > Perhaps it is something to do with afterFind() ? > > John > > > On May 11, 12:27 pm, "Faza" <f...@ansi.pl> wrote: > >> Hi all, >> >> I've run into a weird problem. >> >> I have two models, not directly related, but I need data from model A to >> modify model B find results using ModelB::afterFind(); >> >> In model B, i use this: >> >> $myModelA = ClassRegistry::init('ModelA'); >> >> this returns no error. >> >> but when I do >> $values = $myModelA->findById($valid_id_from_somewhere) >> >> CakePHP fails to load page, but shows no errors. >> >> Anybody have a clue? >> >> thanks in advance... >> -- >> Jacek >> > > > > --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "CakePHP" group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~----------~----~----~----~------~----~------~--~---