http://teknoid.wordpress.com/2008/07/17/forcing-an-sql-join-in-cakephp/ Lapinski ohneworte-2 wrote: > > > Hello Together, > I want to link two Models without using a Foreign Key, but using some > Conditions instead. Here is my example: > > Model: > --------- > class Category extends AppModel { > var $name = "Category"; > var $actsAs = array("Containable"); > > var $hasMany = array( > "Zone" => array( > "foreignKey" => false, > "conditions" => array( > "AND" => array("Category.width = Zone.width", > "Category.height = > Zone.height") > ) > ) > ); > } > > Controller: > -------------- > $category = $this->Category->find("first", array( > "conditions" => array("Category.id" => 1), > "contain" => array( > "Zone" > ) > )); > > Result: > ---------- >>>SQL Error: 1054: Unknown column 'Category.width' in 'where clause'<< > > That seems clear if you make a look on the generated Query: >>>SELECT ... FROM 'zones' AS 'Zone' WHERE (('Category'.'width' = 'Zone'.'width') AND ('Category'.'height' = 'Zone'.'height')) << > > No Join occurs - but why? Can anybody help me out? > I appreciate any help on this issue. > > Regards. > > > > -- View this message in context: http://www.nabble.com/Model-Association-via-%22conditions%22-fails%21-tp23213390p24621578.html Sent from the CakePHP mailing list archive at Nabble.com. --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "CakePHP" group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~----------~----~----~----~------~----~------~--~---
