Good point! Will look into it, but when I do a search now if I type in Mary or mary I get the same results.
What would you suggest? Dave -----Original Message----- From: John Andersen [mailto:j.andersen...@gmail.com] Sent: August-14-09 2:45 AM To: CakePHP Subject: Re: Search function Hi Dave, Congratulations on the job done! Only one small issue/question, do you take into account, that words may be in uppercase/lowercase? Enjoy, John On Aug 13, 11:02 pm, "Dave Maharaj :: WidePixels.com" <d...@widepixels.com> wrote: > This is what I ended up with and works. > > function __quickQuery($string, $rank, $auth) > { > > //create an array of search terms if more than 1 was > entered > $string = split(",", $string); > > $i=0; // This is each counter > // Now build your SQL String > $sql = ""; > foreach ($string as $key => $value) > { > $value = trim($value); > //strip white space befor and after each term > $sql.= "Post.title LIKE '%" . $value . "%' OR > Post.description LIKE '%" . $value . "%'"; > $i++; // Put your counter up by 1 > if($i < count($string)) // Check if your > counter is smaller than amount of values in array, if there are still > values, add a OR > { > $sql.=" OR "; > } > } > > $params = array( > 'conditions' > => array('Post.status' => 0 , 'Post.rank <=' => $rank, $sql), > ............ > So on and on > ))); > > $q = $this->find('all', $params); > > return $q; > > } > > Pass the $sql to the conditions and I end up with Post.title LIKE > '%mary%' OR Post.description LIKE '%mary%' OR Post.title LIKE '%test%' > OR Post.description LIKE '%test%' OR Post.title LIKE '%something%' OR > Post.description LIKE '%something%' > > -----Original Message----- > From: Luke [mailto:eik...@hotmail.com] > Sent: August-12-09 1:45 PM > To: CakePHP > Subject: Re: Search function > > You are missing a few OR in your below text, I have tried it out and > get all the needed OR, did you just keft it out below or what is the issue? > Oh and by the way of course you will need a WHERE aswell in the first > part $sql = "SELECT * FROM table"; I forgot that one. > > On 12 Aug., 17:00, "Dave Maharaj :: WidePixels.com" > <d...@widepixels.com> wrote: > > Yeah that's the basic idea to build the "Post.title LIKE '%" . $value. > "%' > > OR Post.description LIKE '%" . $value . "%' "; string from the user > > submitted text > > > So if there are 3 words it ends up "Post.title LIKE '%" . $value. "%' > > OR Post.description LIKE '%" . $value . "%' ";"Post.title LIKE '%" . > $value. > > "%' OR Post.description LIKE '%" . $value . "%' ";"Post.title LIKE '%" . > > $value. "%' OR Post.description LIKE '%" . $value . "%' "; > > > -----Original Message----- > > From: Luke [mailto:eik...@hotmail.com] > > Sent: August-12-09 11:43 AM > > To: CakePHP > > Subject: Re: Search function > > > Hi Dave, > > > Maybe not the nicest solution, but this should work: > > > $i=0; // This is your counter > > > // Now build your SQL String > > $sql = "SELECT * FROM table"; > > > foreach ($string as $key => $value) > > { $value = trim($value); > > > //strip white space befor and after each > > term > > // $value = trim($string[$i]); > > $sql.= "Post.title LIKE '%" . $value. "%' > > OR Post.description LIKE '%" . $value . "%' "; > > > $i++; // Put your counter up by 1 > > if($i < count($string)) // Check if your counter is smaller > > than amount of values in array, if there are still values, add a OR > > { > > $sql.="OR"; > > } > > } > > > You can try out by putting in echo $sql at the end. > > > Is this what you were looking for or did I missunderstood? > > > Luke- Zitierten Text ausblenden - > > > - Zitierten Text anzeigen - --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "CakePHP" group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~----------~----~----~----~------~----~------~--~---
